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    <title>Science on Chris Rants at Clouds</title>
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      <title>03/Jun/2026 - Space Science Chats With AI</title>
      <link>https://chris.funderburg.me/posts/2026/06/03/space-science-chats-with-ai-1/</link>
      <pubDate>Wed, 03 Jun 2026 21:25:53 +0000</pubDate>
      <guid>https://chris.funderburg.me/posts/2026/06/03/space-science-chats-with-ai-1/</guid>
      <description>A lazy evening of space science questions with an AI that wasn&amp;rsquo;t afraid to show its working</description>
      <content:encoded><![CDATA[<p>I need to properly make a new blog post as it&rsquo;s been a while, but I got sidetracked with questions about space, speed, g-forces, and fixed points. I present to you, my prompts to Claude&rsquo;s Opus 4.8 model, and its answers.</p>
<blockquote>
<p>Science chat!</p>
<p>Ok, the earth is spinning, and orbiting the sun.  The sun is moving around the the milky way&rsquo;s galactic center.  The milky way is orbiting - something.   If you could somehow define a FIXED point in space - how fast am I, as a human on earth, moving per second way from that fixed point.</p>
</blockquote>
<p>Right, this is a cracking question and the answer involves some beautiful layers of physics. Let me break it all down.</p>
<h2 id="the-fixed-point-problem">The &ldquo;Fixed Point&rdquo; Problem</h2>
<p>First, the philosophical snag: there is no universally agreed fixed point in space. The universe has no centre, no anchor. The best we can do is use the <strong>Cosmic Microwave Background (CMB)</strong> as a reference frame - the afterglow of the Big Bang, which permeates the entire universe and is effectively the closest thing we have to an absolute frame.</p>
<p>Using that as your fixed point:</p>
<hr>
<h2 id="the-stack-of-velocities">The Stack of Velocities</h2>
<table>
  <thead>
      <tr>
          <th>Motion</th>
          <th>Speed</th>
      </tr>
  </thead>
  <tbody>
      <tr>
          <td>Earth&rsquo;s rotation (at ~52° latitude, i.e., you)</td>
          <td>~0.29 km/s</td>
      </tr>
      <tr>
          <td>Earth orbiting the Sun</td>
          <td>~29.78 km/s</td>
      </tr>
      <tr>
          <td>Solar system orbiting galactic centre</td>
          <td>~220-240 km/s</td>
      </tr>
      <tr>
          <td>Milky Way moving through Local Group</td>
          <td>~80 km/s</td>
      </tr>
      <tr>
          <td>Local Group falling toward Great Attractor</td>
          <td>~600+ km/s total</td>
      </tr>
  </tbody>
</table>
<p><strong>But here&rsquo;s the critical bit:</strong> you cannot just add these numbers. They&rsquo;re all vectors pointing in different directions, and some partially cancel depending on time of year and galactic geometry.</p>
<hr>
<h2 id="the-bottom-line">The Bottom Line</h2>
<p>The Sun&rsquo;s total velocity relative to the Cosmic Microwave Background, accounting for all contributions, is approximately <strong>370 km/s</strong>.</p>
<p>Your rotation contribution at 52°N is tiny (~0.29 km/s), so realistically you&rsquo;re sitting at somewhere in the ballpark of <strong>~370 km/s</strong> relative to the CMB.</p>
<p>That&rsquo;s <strong>370 kilometres every single second</strong>. About 1.3 million km/h.</p>
<hr>
<h2 id="the-fun-wrinkle">The Fun Wrinkle</h2>
<p>Your cumulative speed through the Milky Way alone can vary from as little as 208 km/s to as much as 237 km/s depending on whether Earth is travelling in the same direction as the Solar System moves through the galaxy or the opposite direction - and this changes over the course of a year.</p>
<p>So your speed is literally seasonal. You&rsquo;re going faster in some months than others, relative to the galaxy.</p>
<hr>
<h2 id="the-rabbit-hole-gets-deeper">The Rabbit Hole Gets Deeper</h2>
<p>The Milky Way itself is being gravitationally dragged toward the <strong>Great Attractor</strong> (a massive overdensity of matter about 250 million light-years away), and beyond that the <strong>Shapley Supercluster</strong>. That&rsquo;s baked into the 370 km/s figure.</p>
<p>At the absolute largest scale? The entire observable universe is expanding in every direction. &ldquo;Moving away from a fixed point&rdquo; starts to become a philosophically broken concept - spacetime itself is stretching, not objects moving <em>through</em> space.</p>
<p>Einstein sends his regards. The universe is deeply weird and there&rsquo;s no such thing as standing still.</p>
<blockquote>
<p>When they&rsquo;re going to the moon, roughly how fast per second are they moving?</p>
</blockquote>
<p>Great follow-up, because the contrast is stark.</p>
<h2 id="apollo-to-the-moon">Apollo to the Moon</h2>
<p>The rough speeds during a lunar mission:</p>
<table>
  <thead>
      <tr>
          <th>Phase</th>
          <th>Speed</th>
      </tr>
  </thead>
  <tbody>
      <tr>
          <td>Low Earth Orbit (before trans-lunar injection)</td>
          <td>~7.8 km/s</td>
      </tr>
      <tr>
          <td>Trans-lunar injection burn (leaving Earth)</td>
          <td>~10.9 km/s</td>
      </tr>
      <tr>
          <td>Cruising to the Moon (mid-journey, coasting)</td>
          <td>slows to ~1 km/s</td>
      </tr>
      <tr>
          <td>Lunar Orbit Insertion</td>
          <td>~1.6 km/s</td>
      </tr>
      <tr>
          <td>Landing descent</td>
          <td>tens of metres per second</td>
      </tr>
  </tbody>
</table>
<hr>
<h2 id="the-counterintuitive-bit">The Counterintuitive Bit</h2>
<p>The cruise phase <strong>slows down dramatically</strong> because Earth&rsquo;s gravity is still pulling the spacecraft back the whole way. Think of throwing a ball upward - it slows as it climbs. Same principle, just over 384,000 km.</p>
<p>At the <strong>L1 Lagrange point</strong> - roughly 90% of the way to the Moon where lunar gravity starts winning - the spacecraft is at its <em>slowest</em>, around 0.8-1 km/s, before the Moon&rsquo;s gravity starts pulling it back up to speed.</p>
<hr>
<h2 id="the-punchline-vs-your-previous-question">The Punchline vs Your Previous Question</h2>
<p>At ~10 km/s peak velocity, the Apollo spacecraft was moving at roughly <strong>1/37th</strong> of your speed relative to the CMB.</p>
<p>You, sitting completely still in your chair right now, are moving ~370 km/s relative to the CMB. The Apollo astronauts burning their engines as hard as they could managed about 2.7% of that.</p>
<p>Rocket technology is simultaneously one of humanity&rsquo;s greatest achievements and a humbling reminder of how cosmically slow we actually are. We&rsquo;re not going anywhere fast. ✨</p>
<blockquote>
<p>We had a chat a few weeks ago, but I can&rsquo;t seem to find it - about how, if I had a VERY good rocket and an indestructible space suit, and I wanted to go directly opposite of the earth&rsquo;s orbit until my my rotational speed around the sun was zero, how long would it take to fall into the sun.</p>
<p>Now, what I can&rsquo;t remember was, what speed do I need to get the rocket to - relative to earth -  to do that?  And, do we have rockets capable of that speed?</p>
</blockquote>
<p>Got it - found the conversation. The answer was actually already in there. Let me pull out the exact number for you.</p>
<h2 id="the-speed-you-need">The Speed You Need</h2>
<p>From our previous chat, the key figure was buried in the detail:</p>
<blockquote>
<p>To come to rest relative to the Sun you need to cancel <strong>Earth&rsquo;s orbital velocity of 29.78 km/s</strong>. The actual Δv requirement, accounting for also escaping Earth&rsquo;s own gravity well, works out to roughly <strong>√(29.78² + 11.2²) ≈ 31.8 km/s</strong> relative to Earth, fired retrograde (directly opposite Earth&rsquo;s orbital direction).</p>
</blockquote>
<p>So roughly <strong>~30 km/s</strong> is the headline number - that&rsquo;s what you need to zero out your solar orbital velocity. The extra ~2 km/s is the cost of climbing out of Earth&rsquo;s own gravity well first.</p>
<hr>
<h2 id="can-we-do-that">Can We Do That?</h2>
<p>Short answer: <strong>not even close.</strong></p>
<p>The Saturn V + Apollo stack achieved about <strong>~15 km/s</strong> of total Δv, and most of that was spent just getting to LEO (~9 km/s). The trans-lunar injection burn was only about 3 km/s on top of that.</p>
<p>The fastest human-made object ever launched, the <strong>Parker Solar Probe</strong>, reaches around <strong>163 km/s</strong> relative to the Sun - but that&rsquo;s <em>with</em> the Sun&rsquo;s gravity doing the accelerating after multiple Venus gravity assists. Its <strong>launch Δv</strong> was nowhere near that.</p>
<p>To actually <em>cancel</em> 30 km/s of velocity requires an absolutely brutal amount of fuel under the <strong>Tsiolkovsky rocket equation</strong> - propellant requirements scale exponentially with Δv. You&rsquo;d need a rocket so large it essentially can&rsquo;t exist with chemical propellants.</p>
<hr>
<h2 id="the-irony">The Irony</h2>
<p>It is genuinely <strong>harder to hit the Sun than to escape the solar system entirely.</strong> Escape needs ~42 km/s from Earth&rsquo;s surface, but you&rsquo;re already moving at 29.78 km/s in the right direction - so you only need to add ~12 km/s. To fall <em>into</em> the Sun you need to cancel that 29.78 km/s you already have. Working against your own momentum is brutal.</p>
<p>NASA has noted this exact problem. The Parker Solar Probe doesn&rsquo;t even try to go straight in - it uses seven Venus flybys over years to bleed off velocity gradually, because a direct deceleration burn is basically impossible with current tech.</p>
<blockquote>
<p>And also remind me, because I though it was cool:  Let&rsquo;s say I could come to that dead &ldquo;stop&rdquo; in relation to the sun - I&rsquo;d stop orbitting. I remember you said I&rsquo;d fall for about 64 days. How fast would I be moving by the time I hit the sun&rsquo;s atmosphere?  And what was the g-force I&rsquo;d hit on impact?</p>
</blockquote>
<p>From the previous chat, these numbers were in there:</p>
<h2 id="impact-velocity">Impact Velocity</h2>
<p><strong>After 64.5 days falling, your velocity would be ~617 km/s</strong> when you hit the solar surface.</p>
<p>The elegant reason: that&rsquo;s the Sun&rsquo;s <strong>surface escape velocity</strong>. By conservation of energy, falling <em>into</em> a gravity well from effectively infinity accelerates you to exactly the same speed as escaping it would require. 1 AU is close enough to &ldquo;infinity&rdquo; for this purpose that the maths works out cleanly.</p>
<p>For context: that&rsquo;s about <strong>0.2% of the speed of light</strong>.</p>
<hr>
<h2 id="the-g-force-on-impact">The G-Force on Impact</h2>
<p>This is where I need to be honest - the previous chat covered the <em>surface gravity</em> (28x Earth&rsquo;s, so your 90kg becomes effectively ~2,500kg standing on the surface), but the <strong>impact deceleration</strong> depends entirely on <em>how quickly you stop</em>, which depends on the density and depth of the material stopping you.</p>
<p>The honest answer: <strong>the number would be so catastrophically large it&rsquo;s essentially meaningless.</strong></p>
<p>You&rsquo;re hitting tenuous plasma at 617 km/s. The photosphere is actually <em>less dense than Earth&rsquo;s atmosphere</em> at the very top, but it deepens rapidly. You&rsquo;d be decelerating from 617 km/s to zero over some very short distance. Even if it took <strong>100km</strong> to stop you (generous), that deceleration would be roughly:</p>
<p>v² / 2d = (617,000)² / (2 × 100,000) ≈ <strong>~1.9 billion m/s²</strong></p>
<p>That&rsquo;s about <strong>190 million G</strong>.</p>
<p>For reference, a fighter pilot blacks out at ~9G. A bullet experiences ~100,000G. You&rsquo;d be experiencing forces that make a bullet impact look like a gentle hug.</p>
<p>Your indestructible suit would survive. <em>You</em> would become a very thin layer of paste distributed uniformly throughout it.</p>
<p>As always, you can add my <a href="https://chris.funderburg.me/index.xml" target="_blank" >RSS feed</a> to your reader of choice and if you made it this far <strong>thanks for reading</strong>!</p>
<p>Chris</p>
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